4a^2-16a+16-(3a+4)=0

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Solution for 4a^2-16a+16-(3a+4)=0 equation:



4a^2-16a+16-(3a+4)=0
We get rid of parentheses
4a^2-16a-3a-4+16=0
We add all the numbers together, and all the variables
4a^2-19a+12=0
a = 4; b = -19; c = +12;
Δ = b2-4ac
Δ = -192-4·4·12
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-13}{2*4}=\frac{6}{8} =3/4 $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+13}{2*4}=\frac{32}{8} =4 $

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